Quadratic equation solutions programe
Programe is:
#
# Quadratic equation solutions programe
# a*x**2 + b*x + c = 0
#
import cmath
answer = 'y'
while answer == 'y' or answer == 'Y':
a = float(input(' coeficient a is:'))
b = float(input(' coeficient b is:'))
c = float(input(' coeficient c is:'))
gama = 2*a
eta = -b/gama
delta = cmath.sqrt(b*b - 4*a*c)/gama
x_1 = eta - delta
x_2 = eta + delta
print('The solution X1 is:', x_1)
print('The solution X2 is:', x_2)
answer = input(' If you want to continue, type y or Y: ')
print(' Thank you for working with this program!')
#
# Quadratic equation solutions programe
# a*x**2 + b*x + c = 0
#
import cmath
answer = 'y'
while answer == 'y' or answer == 'Y':
a = float(input(' coeficient a is:'))
b = float(input(' coeficient b is:'))
c = float(input(' coeficient c is:'))
gama = 2*a
eta = -b/gama
delta = cmath.sqrt(b*b - 4*a*c)/gama
x_1 = eta - delta
x_2 = eta + delta
print('The solution X1 is:', x_1)
print('The solution X2 is:', x_2)
answer = input(' If you want to continue, type y or Y: ')
print(' Thank you for working with this program!')
Results are:
============ RESTART: /Users/ionivan/Documents/QuadraticEcuation.py ============
coeficient a is:1
coeficient b is:1
coeficient c is:1
The solution X1 is: (-0.5-0.8660254037844386j)
The solution X2 is: (-0.5+0.8660254037844386j)
If you want to continue, type y or Y: y
coeficient a is:1
coeficient b is:5
coeficient c is:6
The solution X1 is: (-3+0j)
The solution X2 is: (-2+0j)
If you want to continue, type y or Y: 1
Thank you for working with this program!
(March 31, 2022)
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